Question

write a quadratic equation for x having the given number as the solution. 10 is solution.

Answer 1

in the form of ax^2+bx+c=0

Answer 2

x^2-20x+100=0

Answer 3

ok so far ive gotten x^2-20

Answer 4

nope wait..

Answer 5

it has to be ax^2+bx+c=0 form.. its not working i came up with that too and it said it was wrong...idk then

Answer 6

mine is of that form,ok try this one:2x^2-19x-10=0

Answer 7

that didnt work but i put in the answer we came up with and said it was wrong and then it gave me the correct asnwer and its the same one we had!! i hate when it does that

Answer 8

ok now i have one using 7 as the solution, i came up with x^2-16x+64=0. would that be right?

Answer 9

it would be x^2-16x+63=0

Answer 10

how did you get 63?

Answer 11

7^2-(16*7)+63=0 that's the meaning of "7 is a solution of this equation"

Answer 12

dont you add 8+8 then multiply and that gives you 64?

Answer 13

that's if u wanted 8 to be a solution of this equation..

Answer 14

oh lord i typed 7 instead of 8 lol im sorry

Answer 15

in general there is an infinite number of equations for which 8 is a solution:

(x-8)(x+1)=0
(x-8)(x+2)=0
.....
just expand to get your quadratic equation

Answer 16

got it thanks!