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solve each equation: 2^3y+1=sqrt2
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is it 3y+1 together?
yes
ok we can write sqrt 2 as 2^1/2 therefore we have 3y+1=1/2 i believe u can go forward with that can you?
we lost the 2 at the beginning of the equation
\[2^{3y+1}=\sqrt{2}\]
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yes
so sqrt2 is also equal to 2^1/2
ok
um so u can go about it? or u still confused?
do I solve for Y now
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yes
cool
No I guess I am still confused
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