Question

4/x + 1/x-2 =1 Please give me an answer! I need a hero here!! I'm running out of time.

Answer 1

He's gotta be strong
And he's gotta be fast
And he's gotta be fresh from the fight!

Answer 2

\[\frac{4}{x} + \frac{1}{x-2} = 1?\]

Answer 3

yes :)

Answer 4

\[\frac{4x -8}{x(x-2)} + \frac{x}{x(x-2)}\]

Answer 5

\[\frac{5x-8}{x(x-2)}\]

Answer 6

4/x + 1/(x-2) = 1
4(x-2)/(x-2)x + x/x(x-2) = 1
[(4x-8)+x]/(x^2 - 2x) = 1
(4x-8)+x = (x^2 - 2x)
5x-8 = x^2 - 2x
x^2 - 7x + 8 = 0
(x-8)(x+1)=0
x=8, x=-1

Answer 7

\[x=\frac{7\pm\sqrt{17}}{2}\]

Answer 8

*hug* thanks so so so much, wait a sec, if you dont mind. i have more

Answer 9

go ahead and post

Answer 10

ok just a sec :)

Answer 11

\[2/x^2-3x+2=3x/x-1-x/x-2\]

Answer 12

\[\frac{2}{x^2-3x+2}=\frac{3x}{x-1}-\frac{x}{x-2}\] like that?

Answer 13

if so try
\[x=\frac{5\pm\sqrt{41}}{4}\]

Answer 14

ok be right back... :)

Answer 15

awesome thanks so much! can you help me with two more? thats all i have left :D

Answer 16

\[4x=\sqrt{2x+3}\]