Ask
your own question, for FREE!
Mathematics
8 Online
Find the area of the region bounded by the graph of y^2 = -4(x-1) and y^2 = -2(x-2). Provide a graph.
Still Need Help?
Join the QuestionCove community and study together with friends!
\[y^2=-4(x-1)\quad,\quad x=1-\frac{y^2}{4}\]\[y^2=-2(x-2)\quad,\quad x=2-\frac{y^2}{2}\]\[-4(x-1)=-2(x-2)\quad,\quad x=0\quad\Rightarrow\quad y=\pm 2\]\[S=\int\limits_{-2}^{2}\left(2-\frac{y^2}{2}-1+\frac{y^2}{4}\right)dy=\int\limits_{-2}^{2}\left(1-\frac{y^2}{4}\right)dy=\int\limits_{0}^{2}\left(2-\frac{y^2}{2}\right)dy=\]\[=\left(2y-\frac{y^3}{6}\right)|_0^2=4-\frac{4}{3}=\frac{8}{3}\] http://www.wolframalpha.com/input/?i=y%5E2%3D-4%28x-1%29+and+y%5E2%3D-2%28x-2%29
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
VERNEISH:
Two objects are moving along separate linear paths where each path is described by position, d, and time, t.
Maci:
what are the best stock apps for people who want to start investing?
Twaylor:
genuienly how do i get better self control i keep watcing youtube and theres this
IzzyCookie:
|dw:1792074056138:dw| Uhm, I don't know where to ask this, but I'm in college welding at my community college, and I need help learning vertical welding for
thehearken:
not sure if this is considered spam, im sorry if it is, but does anyone have tips
21 hours ago
0 Replies
0 Medals
4 days ago
3 Replies
2 Medals
1 week ago
3 Replies
0 Medals
2 days ago
9 Replies
1 Medal
1 week ago
2 Replies
1 Medal