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Mathematics 22 Online
OpenStudy (anonymous):

can you determine the zeros of F(x)=x^2 +64 by using a graph? explain why or why not please help me out

OpenStudy (anonymous):

yes, the zeros are where the curve crosses the x - axis

OpenStudy (anonymous):

and this one clearly doesn't. but you don't need a graph for that for any x \[x^2\geq0\] so \[x^2+64\geq64\] and so it is never 0

OpenStudy (anonymous):

thanks guys

OpenStudy (anonymous):

if you meant \[x^2-64\] then the zeros are -8 and 8 by inspection

OpenStudy (anonymous):

no just x^x+64

OpenStudy (anonymous):

i mean x^2

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