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OpenStudy (anonymous):
How do i find the excluded value of this denominator?
r^3−r^2−49r+49
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OpenStudy (kira_yamato):
Let the denominator = 0
OpenStudy (anonymous):
how?
OpenStudy (kira_yamato):
Solve the eqn = 0
OpenStudy (anonymous):
i learned that we factor it first and equal it to zero
OpenStudy (anonymous):
how do i solve it? it doesn't have a common factor
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OpenStudy (cwrw238):
try finding a factor using factor theorem
OpenStudy (anonymous):
thanks i'll learn that go learn that
i haven't learned that yet
OpenStudy (cwrw238):
x-7 is worth trying (as last term = 7^)
f(7) = 343 - 49 - 343 + 49 = 0
ok so (x-7) is a factor
now find any other factors by dividing by x-7
OpenStudy (cwrw238):
factor theorem if f(x) is divisible by x-a then f(a) = 0
OpenStudy (cwrw238):
r^2 +6r - 7
----------------
r-7 ) r^3−r^2 −49r+49
r^3 -7r^2
--------
6r^2 - 49r
6r^2 - 42r
---------
-7r + 49
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OpenStudy (cwrw238):
r^2 +6r - 7 = (r+7)(r-1)
so factors of f(r) =
(r-7)(r+7)(r-1)
OpenStudy (cwrw238):
so excluded value is value of f(r) when r=7,-7 or 1
OpenStudy (kira_yamato):
Yes
OpenStudy (kira_yamato):
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