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Five candidates-A,B,C,D and E were in an election. Canidate A was elected with 30 votes,B placed second and E was in last with 3 votes. If 59 votes were cast, and no two candidates had the same number of votes, what is the smallest number of votes thet B could have received?
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A - 30 B - x C - y D - z E - 3 59 - 33 = 26 x+y+z = 26 None of them can have the same number of votes. so x > y > z
z has to have at least 4 votes y has to have at least 5 votes x will have the rest 17
I had a solution similar to yours, I went about it in a different way. Got the same numbers
thank you guys so much
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How about B 10 C 9 D 7
Yeah, I figured I went about this the wrong way.
Phi has it
But Phi, next time, you should post your steps
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