Mathematics
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OpenStudy (wondermath):
Solve the trig equation sin2x=1/3
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OpenStudy (akshay_budhkar):
sin2x=1/3
2x=sin^-1(1/3)
x=[sin^-1(1/3]/2
OpenStudy (anonymous):
are you sure ?
OpenStudy (akshay_budhkar):
yes
OpenStudy (wondermath):
yeah i got that, but there is more than one answer
OpenStudy (anonymous):
sin2x=2sinxcos which is a trig identity
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OpenStudy (akshay_budhkar):
yea
the other answer is
sin2x=1/3
2x=(pie)-sin^-1(1/3)
OpenStudy (akshay_budhkar):
um as sinx takes the value twice in 0 to pie..
OpenStudy (akshay_budhkar):
you get it?
OpenStudy (akshay_budhkar):
@salem yes correct.. so what is x using that formula?
OpenStudy (wondermath):
actually in the back it has 4 answers
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OpenStudy (wondermath):
i got the firs two
OpenStudy (akshay_budhkar):
4 answers lol
OpenStudy (wondermath):
lol yea
OpenStudy (akshay_budhkar):
actually it has infinite solutions
OpenStudy (wondermath):
LOL
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OpenStudy (akshay_budhkar):
sinx is a continuous curve
OpenStudy (wondermath):
no sorry forgot to say its from 0 to 2pi
OpenStudy (anonymous):
thanks for correction Akshay
OpenStudy (akshay_budhkar):
umm lol lemme think i have not done trigo for a while.. u gotta use the formulae like sin 2(pie) + x=sinx and stuff
OpenStudy (anonymous):
you mean getting the function back to its the original for
or use trig identity for angles
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OpenStudy (akshay_budhkar):
sorry wondermath my brain needs to dig it out now lol .. i will ask some1 to help u :P do u get the concept?
OpenStudy (wondermath):
lol okay thanks