Question

2sinx-2sinxcosx^2x+1-cos^2x

Answer 1

what are we doing?

Answer 2

i think he wants it simplified o.O

Answer 3

I can rewrite it
I don't know if it is considered simplified

\[2\sin(x)-2\sin(x) \cos^2(x)+1-\cos^2(x)=2\sin(x)(1-\cos^2(x))+1-\cos^2(x)\]
\[=2 \sin(x) (1-\cos^2(x))+1(1-\cos^2(x))=(1-\cos^2(x))(2 \sin(x)+1)\]
\[\sin^2(x)(2 \sin(x)+1)\]

Answer 4

umm yea looks good myininaya.. or maybe that stuff is 0..so we can find x i believe

Answer 5

good esp

Answer 6

if so set both factors =0

Answer 7

yea :D

Answer 8

It says "Solve each equation for \[0 \le x < 360\]

Answer 9

it is not an equation <.<

Answer 10

just so you know you didn't write in equation

Answer 11

an*

Answer 12

it is an expression

Answer 13

so it is =0 like akshay said?

Answer 14

yes, it is equal to 0

Answer 15

so i factored your expression
set both of the factors in my expression =0

Answer 16

can you do that?

Answer 17

a*b=0 => a=0 or b=0 or both=0

Answer 18

Habu can u proceed further? or do u want it to be done?

Answer 19

Can you write it all out please and thank you (:

Answer 20

\[\sin^2(x)(2 \sin(x)+1)=0 => \sin^2(x)=0 \text{ or } 2 \sin(x)+1=0 \]

Answer 21

you have two equations to solve

Answer 22

sin(x)=0 is the easiest

Answer 23

sin(0)=0 right
so x=0 is one solution
now you try to solve 2sin(x)+1=0

Answer 24

i will give you a clue
subtract one on both sides
then
divide 2 on both sides

Answer 25

x=180 is another soluton of sinx=0 :)

Answer 26

oh yes and that one

Answer 27

will do the second one?
@myininaya you r too quick lol :P

Answer 28

7pie/6 and 11pie/6

Answer 29

yes correct :)

Answer 30

Thank you both for your help (:

Answer 31

yw :D.. lol thank myininaya i did nothing :D

Answer 32

i would write my answer in degrees since your inequality is written in degrees