Question

If the cos(x) = -12/13, and tan(x) < 0, find
sin(x)
tan(x)
sec(x

Answer 1

tan(x)=sin(x)/cos(x) so than sin(x)=tan(x)*cos(x) so than result that because cos(x) is negativ and tan(x) is less than zero than result that sin(x) will be always positive

Answer 2

there is a right angled triangle with sides 5,12,13 and cos x = -12/13 and tan x < 0 means that x is in the second quadrant so
sinx = 5/13
tan x = -5/12
secx = -12/5

Answer 3

dont know why this last post was duplicated!