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3= |x |/12 +3
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\[x=45\]\[3\times15=x\]\[3=x \div15\]\[3=x \div12+3\]
Assuming your question is:\[3=\frac{|x|}{12+3}\]then you would first add the 12 and 3 in the denominator to get 15, giving you:\[3=\frac{|x|}{15}\]next, to get rid of the 15 in the denominator, multiply both sides by 15 to get:\[45=|x|\] now, do you know what |x| means?
x = -45 x = 45
because |-45| = 45 and |45| = 45
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