Question

I am doing integrals by substitution, U=lnx, dx=(du/(1/x) please tell me if there is a better way to plot that, or if I messing up something.

Answer 1

what is your original integral?

Answer 2

is \[\int\limits_{}^{}(lnx)^6\div x dx\]

Answer 3

Let
u= ln x
du = 1/x dx
That gives us:
\[\int u^6 du = \frac17 u^7 + C\]
plug back in for u:
\[=\frac{(\ln x)^7}{7}+C\]

Answer 4

Thanks man

Answer 5

no problem--it looked like you were basically there, you just havent gotten the hang of substitution all the way yet :P