Question

for the following eqution state the vale of the describe the nature of the solutions
13x^2+9x-5=0

Answer 1

two real zeros. nice and ugly ones

Answer 2

use
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{a}\] with
\[a=13,b=9, c=-5\] and compute carefully

Answer 3

typo there should be
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]

Answer 4

/me wonders wheres edit button

Answer 5

discriminant
b^2 -4ac
if that is greater than or equal to 0, then the roots are real