You are on a game show. Three doors appear before you, each one with a prize behind it. Behind one is a car, and behind two others are goats. You are asked to select a door (all the doors are currently closed). Once you have selected that door, the host does not open that door door immediately. Instead, he opens a door that you have not chosen, revealing a goat. He then gives you an option to switch your choice to the other undisclosed door. What is the probablity of winning the car if you switch?
2/3 google monte hall problem and get the solution
Wow ... I'm impressed. Did you see this problem before?
it's a famous problem
Lol ... I guess you guys are pretty experienced. I only saw this problems two weeks ago.
problem*
or try it for yourself here http://www.stat.sc.edu/~west/javahtml/LetsMakeaDeal.html or here http://www.shodor.org/interactivate/activities/SimpleMontyHall/ or get a solution here http://homepages.sover.net/~nichael/puzzles/monty/
Explain your reasoning?
famous problem, with lots of controversy when it came out
reasoning? i will give you a simple but not perhaps correct reason. it is pretty clear, assuming that you have no knowledge of the door and monty has the prize hidden at random, that if you do not switch your chances of winning are one is three. hence if you switch it is two in three. if that is not satisfactory, then we have to do more work. if the prize is behind door 1, you pick door 1. you switch, you lose if it is behind door two, you pick door one, you switch, you win if it is behind door 3, you pick door 1, you switch, you win so you win two out of three times
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