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Mathematics 11 Online
OpenStudy (anonymous):

ATT Satellite: Please help

OpenStudy (anonymous):

OpenStudy (anonymous):

Thanks for makin an appearence

OpenStudy (anonymous):

M=K(r-ln(1+r))

OpenStudy (anonymous):

\[M=K(r-\ln(1+r))\] \[M'=K(r'-\frac{r'}{1+r})\]

OpenStudy (anonymous):

and that is the whole answer?

OpenStudy (anonymous):

that is what i get, yes

OpenStudy (anonymous):

They should have asked it in a simpler form!!!!!!

OpenStudy (anonymous):

i suppose you could change the notation and write \[\frac{dM}{dt}=K(\frac{dr}{dt}-\frac{1}{1+r}\frac{dr}{dt})\] but it means the same thing

OpenStudy (anonymous):

ya I just wished they asked to find the derivative with respect to time> i wld get what to do in a second

OpenStudy (anonymous):

These textbooks drive me crazy

OpenStudy (anonymous):

Thanks for your help

OpenStudy (anonymous):

yes they are good at being annoying like that yw

OpenStudy (anonymous):

I may be back for more so we will BIT

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