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Mathematics 16 Online
OpenStudy (anonymous):

solve sqrt9x+55=x+5

OpenStudy (amistre64):

if you could graph them, the points where they intersect are the solutions

OpenStudy (amistre64):

otherwise, you have to square both sides and work it from that angle and dbl chk the results for extranuous results

jhonyy9 (jhonyy9):

sqrt9x or sqrt(9x+55) ???

OpenStudy (anonymous):

it sqrt 9x+55

OpenStudy (anonymous):

so then it would be 0 right that is what i got

jhonyy9 (jhonyy9):

after squared both sides you get 9x+55=x2 +10x +25 x2 +x -30=0 x_1,_2=(1+/- sqrt(1+120))/2 =(1+/- sqrt121)/2 = -5 and 6

OpenStudy (amistre64):

\[\sqrt{55}\ne5\]

OpenStudy (anonymous):

so then where did i go wrong if i got 0 instead of sqrt 55 =5

OpenStudy (anonymous):

man i messed that up let me try again \[9x+55=x^2+10x+25\] \[x^2+x-30=0\] \[(x-5)(x+6)=0\] \[x=5,x=-6\] now we check

OpenStudy (anonymous):

replace x by 5 to get \[\sqrt{9\times 5+55}=5+5\] \[\sqrt{100}=10\] \[10=10\] that one checks

OpenStudy (anonymous):

\[\sqrt{9\times (-6)+55}=-6+5\] \[\sqrt{1}=-1\] nope

OpenStudy (anonymous):

so answer is \[x=5\]

OpenStudy (anonymous):

thank you

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