FInd tangent line of y=x^2-4x+3 , which goes through point m(2;-5)

Question

anonymous · Answer

calculator?

anonymous · Answer

y = -5

mathteacher1729 · Answer

How far did you get with this problem before getting stuck?

anonymous · Answer

i'm not really sure , where to start .

anonymous · Answer

Start by differentiating your line. This gives you the function to find the gradient of your tangent line you then find the y intercept by inputting the values of your point m.

mathteacher1729 · Answer

Is that EXACTLY how the problem is phrased? It seems a bit ambiguous.

anonymous · Answer

I translated it from a different language , so I'm not sure , whether it's correct or not .

anonymous · Answer

Answers are supposed to be , y=4x-13 and y=-4x+3

mathteacher1729 · Answer

Ah,  I see.  Here's a pic.  Basically you want a line (or lines) that goes through the point (2,-5) and is tangent to the parabola y = x^2 -4x + 3.