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FInd tangent line of y=x^2-4x+3 , which goes through point m(2;-5)
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calculator?
y = -5
How far did you get with this problem before getting stuck?
i'm not really sure , where to start .
Start by differentiating your line. This gives you the function to find the gradient of your tangent line you then find the y intercept by inputting the values of your point m.
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Is that EXACTLY how the problem is phrased? It seems a bit ambiguous.
I translated it from a different language , so I'm not sure , whether it's correct or not .
Answers are supposed to be , y=4x-13 and y=-4x+3
Ah, I see. Here's a pic. Basically you want a line (or lines) that goes through the point (2,-5) and is tangent to the parabola y = x^2 -4x + 3.
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