determine the intervals of increasing and decreasing, as well as all critical points for h(x)=x^4-4x^3+10. give the critical points in x-y coords.
http://tutorial.math.lamar.edu/Classes/CalcI/ShapeofGraphPtI.aspx This is a super duper tutorial on how to graph a function without using a calculator using 1st and 2nd derivatives. :)
h(x)=x^4-4x^3+10 h'(x)=4x^3-12x^2 set it = to 0 and solve
i got 3
it was after that step i don't know what to do
x=0,3
check x<0 check 0<x<3 check x>3
for x=-1 4x^3-12x^2 -4-12=-16 negative number so function is decreasing x<0
-,-,+????
what?
you told me to check the values at the certain places and i got a -/-/+
dec/dec/inc.... would be another way of saying it
confirmed http://www.wolframalpha.com/input/?i=Plot%5Bx%5E4-4x%5E3%2B10%2C%7Bx%2C-2%2C5%7D%5D
thank you for that... and the critical points would be 3 and 0? and i'm not sure how to give them in xy coords
(3,0) (0,0)
on that graph though... those aren't the spots they change concavity or whatever else... its' more like (3,-3) (0,10)
by x,y coords, they mean x,h(x) coords i.e. y is just h(x) when you plot this function
so are the points 3,0 and 0,0
you want h(3) and h(0) for the second coord
thanks
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