Suppose you just received a shipment of twelve televisions. Three of them are defective. If two televisions are randomly selected, what is the probability that both televisons work? What is the probability that at least one does not work?

Question

anonymous · Answer

(9 / 12) * (8/11) for the first one
1 - the above answer for the second one

anonymous · Answer

How would you write that as a fraction?

anonymous · Answer

72 / 132 then simplify

anonymous · Answer

Oh, right. Sorry im being lazy using a calculator. Thanks!

anonymous · Answer

So lets say it were 14 tv's and 4 were defective, would it be worked out like:
(10 / 14) * (9/ 13) for the first one?

anonymous · Answer

Yup

anonymous · Answer

It only simplifies down to 45/91..thats kind of big, no?

anonymous · Answer

thats roughly a half, why would you think thats too big?

anonymous · Answer

Idk just the numbers themselves seem kinda big. But thanks again.

anonymous · Answer

How did you derive at 8/11?