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Use the Law of Cosines to solve the triangle to find the length of b, if A= 48degrees, b = 3, and c = 14.
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\[a^2=b^2+c^2-2bc \cos A\] \[a^2=3^2+14^2-2(3)(14) \cos 48\] \[a = 12.20\]
i agree with matt
I'm assuming you wanted to find the length of a, not b.
I agree with DHASHNI :P
Haha yeah I did. Thanks you guys
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@matt: you foun the length of 'b' and labelled it as 'a' your answer is correct
No dakid91 said b twice in the question, but since angle A and side b were given, I assumed we were going for side a haha
LOL
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