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Mathematics 20 Online
OpenStudy (anonymous):

How can I prove that the square root of three is irrational??

OpenStudy (anonymous):

Contradiction Assume \(\sqrt{3}\) to be rational

OpenStudy (anonymous):

and then what, try and turn it into a ratio?

OpenStudy (anonymous):

\[\sqrt{3} = \frac{p}{q}\]

OpenStudy (anonymous):

enter the square root of 3 in a calculator and you will get a non terminating decimal, so it is irrational.

OpenStudy (anonymous):

Hmm It's been a while since i have done this so I am not sure hmm now p = k *q

OpenStudy (anonymous):

what is k?

OpenStudy (anonymous):

K is a number rational number

OpenStudy (anonymous):

any number?

OpenStudy (anonymous):

\[3 = \frac{p^2}{q^2}\] maybe

OpenStudy (anonymous):

that is where I am

OpenStudy (anonymous):

you divide the whole thing by q^2, then I hit a brick wall

OpenStudy (anonymous):

hmm maybe google can help

OpenStudy (anonymous):

\[3q^2 = p^2 \] \[\text{ http://answers.yahoo.com/question/index?qid=20070313114325AAalFtN }\]

OpenStudy (anonymous):

so k is the short hand for any any integer

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