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How can I prove that the square root of three is irrational??
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Contradiction Assume \(\sqrt{3}\) to be rational
and then what, try and turn it into a ratio?
\[\sqrt{3} = \frac{p}{q}\]
enter the square root of 3 in a calculator and you will get a non terminating decimal, so it is irrational.
Hmm It's been a while since i have done this so I am not sure hmm now p = k *q
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what is k?
K is a number rational number
any number?
\[3 = \frac{p^2}{q^2}\] maybe
that is where I am
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you divide the whole thing by q^2, then I hit a brick wall
hmm maybe google can help
\[3q^2 = p^2 \] \[\text{ http://answers.yahoo.com/question/index?qid=20070313114325AAalFtN }\]
so k is the short hand for any any integer
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