Question

Solve the problem.
Instruments on a satellite measure the amount of power generated by the satellite's power supply. The time t and the power P can be modeled by the function P = 50e^{-t/300}, where t is in days and P is in watts.
How much power will be available after 378 days? Round to the nearest hundredth.


a. 141.8 watts
b. 14.18 watts
c. 1.41 watts
d. 0.14 watts

Answer 1

Are you sure?

Answer 2

25% chance :)

Answer 3

no im not

Answer 4

Why not just plug in t = 378 in the expression?

Answer 5

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Answer 6

Jajaja you are funy...

Answer 7

Plugging in t = 378 gives 14.18 watts, option b. If I have understodd the problem, this is correct.

Answer 8

Elekt how can be sure that this the right answer?

Answer 9

Well, if I have understood the problem, it asks how much power it is after 378 days. Since you have a function that describes the amount of power at any instant t, it should just be to plug in t = 378 days when t is in days :)

Answer 10

ok you are right... thanks... i have mor question dear can you keep helping me ?

Answer 11

Yes, sure :)

Answer 12

List all the elements of B that belong to the given set.
\[B =\left\{ 5,\sqrt{7,-3.0,} \right\} 0>5 0.62\]
Rational numbers
a. \{5,0\}
b. \{\sqrt{7},\frac{0}{5},0.62\}
c. \{ \sqrt{7} \}
d. \{5,-3,0,\frac{0}{5},0.62\}

Answer 13

Hmmz, not even sure what that means because of the \[0 > 50.62\] in there :P

Answer 14

And are you just supposed to list the rational elements of that set?