Two boats move on the same flat lake. At noon boat B is 10 miles east of boat A. For the rest of the day, both boats sail at 10 mph, however boat A sails north and boat B sails east. A. let x be the distance that boat B has traveled east since noon and let y be the distance A has traveled north since noon. Express the distance d between the boats in terms of x and y. B. Use the Chain Rule to differentiate d with respect to t. C. Find the values of x and y at 3pm. D. Use the information in (b) and (c) to calculate the rate of change of the distance between the boats at 3PM.
x = 30 y = 40 Rate of change is 3/4
I did all of that without calculus
what is the answer for A?
what about B? show me the equation.
Wait, let me fix it
(x+10)^2 + y^2 = d^2 I'm not doing B
You're gonna have to figure that out yourself
=.=
This question sucks and I was able to avoid calculus because I knew it sucked. Repost it again and let someone else try
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