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8(t-2)>3(t-9)
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8t - 16 > 3t - 27 can u solve?
8(t-2)>3(t-9) 8t-16>3t-27 8t>3t-27+16 8t-3t>-27+16 5t>-27+16 5t>-11 t > -11/5
Partially, I got to -11/5 . I really hate fractions so I converted it to 2.2 .."/
-2.2 is the same as -11/5, so either way it'll depend on the book/teacher
How do I write it in interval notation though ?
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\[\Large \left(-\frac{11}{5},\infty\right)\]
or you can write it as \[\Large \left(-2.2,\infty\right)\]
Thank you so much. I get confused with the way I write those ..
np
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