Question

how to work out 30th term of 8,11,14,17?

Answer 1

What's the fifth term?

Answer 2

20

Answer 3

So how did you get that?

Answer 4

add 3

Answer 5

exactly. So if the first term
x1 = 8,
then
x2 = 11 = x1 + 3
x3 = x1 + 3 + 3 = x1 + (3-1)*3
x4 = x1 + (4-1)*3

so, what's the expression for the 30th term?

Answer 6

t30 = 1 + (30-1)3 = 88
but when i do it manually by adding 3 it comes up as 95
how do i work it out so it comes to 95

Answer 7

x30 = x1 + (30-1)*3, where x1 = 8

Answer 8

this series forms an Arithmetic PRogression...
where first term is 8 and common difference is 30

T30 = 8 + (30-1)*3
T30 = 8 + 87
T30 = 95..

is this correct ??

Answer 9

yh thanks man

Answer 10

x = a+ (n-1)d
x=8+(30-1)3
8+87=95

Answer 11

your welcome :)

Answer 12

what is first 6 terms in the expansion of 1/(1-3x)^5

Answer 13

can someone help me on this i dont get it

Answer 14

what are the values when x=(1,2,3,4,5 and 6)