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Write log^2 4 + log^2 3 as a single logarithm.
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\[\Large \log_{2}(4)+\log_{2}(3)\] \[\Large \log_{2}(4*3)\] \[\Large \log_{2}(12)\] So \[\Large \log_{2}(4)+\log_{2}(3)=\log_{2}(12)\]
I'm using the idea that \[\Large \log_{b}(x)+\log_{b}(y)=\log_{b}(xy)\]
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