what is the equation of the line that passes through (-2,-3) and is perpendicular to 2x-3y=6?

Question

mertsj · Answer

The slope of 2x-3y=6 is 2/3 so the slope of the perpendicular is -3/2  Now write the equation of a line whose slope is -3/2 and contains the point (-2,-3)

anonymous · Answer

thank you..help me with another?

anonymous · Answer

write the equation of the line that passes through (-2,1) and is perpendicular to the line 3x-2y=5

mertsj · Answer

The slope of 3x-2y = 5 is 3/2  so the slope of the perpendicular is -2/3  So write the equation of a line whose slope is -2/3 and contains the point (-2,1)

anonymous · Answer

&& what is the equation of the line that passes through (-2,3) and is parallel to 2x+3y=6?

mertsj · Answer

if it is parallel, it has the same slope.  The slope of 2x+3y = 6 is -2/3  so write the equation of  line whose slope is -2/3 and contains (-2,3)