Question

is cos= sin/sin?

if not, what is it?

Answer 1

no. cosine = side adjacent/hypotenuse

Answer 2

well can someone explain this pls

Prove that this is true?
1 + csc(x)/sec (x) = cos(x)+cot(x

(1 + csc) / sec = (1 + 1/sin) / (1/cos) = (sin/sin + 1/sin) / (1/cos) = [(sin + 1)/sin] / 1/cos = cos(sin+1)/sin

cos + cot = cos + cos/sin = cos(sin)/sin + cos/sin = [cos(sin) + cos]/sin = cos(sin+1)/sin

cos(sin+1)/sin = cos(sin+1)/sin

Answer 3

1 + csc x / sec x = 1 + 1/sinx / 1/cos x = 1 + cot x
- the first identity is not true

Answer 4

oh its (1 + csc x ) / sec x right?

Answer 5

yea

Answer 6

(1 + csc x ) / sec x = 1 + 1/sin x) / 1/cos x
=[(sinx + 1) / sin x ] * cos x
=cot x ( sin x + 1)
= cos x + cot x

Answer 7

oh wow thanks...could you help me with another one pls.
sin^2 ( x) tan^2 ( x)sin^2 (x )= tan^2 (x )

Answer 8

are you sure about this one?
it doesnt make sense as it stands

Answer 9

\[\sin ^{2}x +\tan ^{2}x \sin ^{2}x=\tan ^{2}x\]

Answer 10

does that look better