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How to solve this non-linear differential equation: y''-x*y'''+(y''')^3=0 @Mathematics @Calculus1
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\[y''-xy'''+(y''')^3=0\]
That is NOT calculus 1. Though I guess there is no differential equations section...
If the equation is with (y'')^3, then the equation is xu' - u = u^3, where u = y'' This is a Bernoulli equation and very doable. But if the equation is as written, ...
it is as written.
Writing as before u = y'', use an Ansatz of u = Ax + B u' = A Then as u - xu' + (u')^3 = 0, Ax + B - Ax + A^3 = 0 => B = -A^3 i.e., u = Ax - A^3 Now integrate twice to find y
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