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sum of x^n*2^n from n=1 to inf
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remember, whenever you multiply with exponents, the exponents are added. So, to solve your problem, you would need to take x and multiply it by 2 and then take the two "n" and add them together 2 * x is 2x n + n = 2n So your final answer would be 2x^2n
S= a/(1-r) a is your first term so it would be a=2x r is your common ratio (which is just the 2nd term divided by the first term) r=2x sub it in and you would get S = 2x/(1-2x)
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