Question

Solve. Please show your work.

√(2x+1)=x-1

Answer 1

\[\sqrt{2x+1}=x-1\]

Answer 2

\[ \sqrt{2x+1}=x-1\]
Take a square on both sides,.
\[ (\sqrt{2x+1})^2=(x-1)^2\]
this will help in getting rid of the square root,
\[2x+1 = (x-1)^2\]
using FOIL to solve the right side.
\[2x+1=x^2-2x+1\]\[x^2+4x=0\]
after solving u will get,
x=4 and x=0

Answer 3

now use them to check in the original equation,

insert 0 first
√(2x+1)=x-1
sqrt(2(0)+1) = 0-1
sqrt 1 = -1

so zero is not a solution,
next check with 4.

insert 4
√(2x+1)=x-1
sqrt(2(4)+1) = 4-1
sqrt9 = 3
3 = 3

So this proves that ONLY FOUR is your solution/answer.

Answer 4

i hope that will help u. =)

Answer 5

lil, do u get it as well?