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OpenStudy (mertsj):
y=2/cosx
OpenStudy (anonymous):
what?
OpenStudy (anonymous):
but de equation
OpenStudy (mertsj):
Exactly
OpenStudy (anonymous):
ok but y=2/cosx
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OpenStudy (anonymous):
??
OpenStudy (anonymous):
What exactly are you supposed to do? Solve for x?
OpenStudy (anonymous):
-rad/3<X<rad/3 and 5rad/3 <X<7rad/3
OpenStudy (anonymous):
x
OpenStudy (mertsj):
The problem is, giovana, that you never asked a question.
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
i need y
OpenStudy (anonymous):
If so, then you could go further from
y=2/cosx
to...
y/2=1/cosx
cross multiple to get...
cosx = 2/y
then...
x = cos^(-1)[2/y]
OpenStudy (anonymous):
you wrote
\[y=2\sec(x)\] but there is no question here. you already have y,
\[y=2\sec(x)\]
OpenStudy (anonymous):
the question could be something like
1) graph
2) evaluate if x = some number
3) find the domain
something of that sort. an equation is not a question
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OpenStudy (anonymous):
What did you mean by "-rad/3<X<rad/3 and 5rad/3 <X<7rad/3" ? Is that the domain this is bound in? What does rad mean?
OpenStudy (anonymous):
2
OpenStudy (anonymous):
rad
OpenStudy (mertsj):
y depends on what x is. You cannot tell what value y has unless you specify a x value
OpenStudy (mertsj):
Why don't you post the directions.
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OpenStudy (anonymous):
=/
OpenStudy (anonymous):
@giovana there are a lot of people here anxious to help you, but you really need to ask a question
\[y=2\sec(x)\] is not a question, it is just an equation. like
\[y=x^2\] or
\[y=\frac{1}{x}\]