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@satellite73, how do you reckon I should state the zeros....
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like this
I dont understand the format it should be in..
ok we factored it right?
yes,
(3x-1)(3x+1)(3x-i)(3x+i)
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then we set each factor equal to zero and solve for x ( in our heads)
which is positive and negative 1/3 but what about the ones in paranthesis with i?
\[3x-1=0\implies x=\frac{1}{3}\] etc
same with them \[3x-i=0\] \[x=\frac{i}{3}\]
okay
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got it?
let me see if it accepts it
you will have 4 zeros, each with multiplicity 1
okay thank u!
yw
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