How to integrate (x^2 -1)/x? Do I use u-substitution?

Question

anonymous · Answer

what can you do here? Can you use algebra to make this problem easier before you integrate?

anonymous · Answer

do you mean long division?

anonymous · Answer

nah just divide each term by x

anonymous · Answer

$$\frac{x^2-1}{x}=x-\frac{1}{x}$$

anonymous · Answer

try splitting up the fraction...as sat as done

anonymous · Answer

oh I see. so in the end the answer would be $$1/2x ^{2}-\ln \left| x \right|+ c?$$

anonymous · Answer

thank you!

anonymous · Answer

good, but always try and look for algebra tricks before doing the integral It will help you in the long run!

anonymous · Answer

yes, after you told me told me that I felt really dumb. i'll definitely try to do that in the future.

anonymous · Answer

good you will do fine.  also just because someone just easily gives you the answer doesn't mean you shouldn't try and figure it out for yourself.

anonymous · Answer

thanks for the advice. sometimes i want to quit but i really want do well on the bc exam. so i keep trying to understand what im doing. you are so encouraging, seriously.