Question

Solve by using the quadratic formula.

x2 − 6x + 39 = 0

Answer 1

a = 1
b = -6
c = 39

so now the formula for quadratics is \[-b + \sqrt{b^2 - 4ac} / 2a\]

Answer 2

so now substitute and valuate

Answer 3

i don't get it

Answer 4

http://www.purplemath.com/modules/quadform.htm

Answer 5

someone help me please

Answer 6

x_1,_2=(6+/- sqrt(36-156))/2 =(6+/- sqrt(-120))/2 =(6+/- 2isqrt(30))/2 =
=3+/- isqrt30