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factor v^2+6v+9=(v+2)(v+3)?
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no. to factor a quadratic, find factors of the last number (9) so that they add up to make the middle number (6) the correct factors for this would be (x+3)(x+3)
close, v^2+6v+9=(v+3)(v+3) which condenses to v^2+6v+9=(v+3)^2
ok how do i get the 6v?
Using FOIL, we get (v+3)(v+3) v^2+3v+3v+9 v^2+6v+9
ok then combine like terms?
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exactly
ok so should i write my anwer as (v+3)(v+3) or (v+3)^2
That really doesn't mater
(v+3)^2 is simpler to write
is that factored compleley?
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yes
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