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Solve: log2 (x) +log2(x+7) =3 (2 is the base)
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do you know the logarithm rules?
Yeah i am just really bad at logarithms
ok you know that \[ \log_a (xy) = \log_a x + \log_a y\]
yes i do i have done that part but i dont know how to continue it from there
ok so\[\log_2 x(x+7)=3\]
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Whenever you have\[\log_b A =x\]that means\[b^x=A\]
yeah okay so, do you multiply the x(x-7) ?
yep
how about this question, 4logx(2) = log 2(x) [x and 2 are the bases] is it like this, logx(2^4) = log2 (x) log2(2^4)/ log 2(x) = log 2(x) 4/log2(x) = log2(x) how do i continue from here ?
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