Evaluate the following function at the indicated values. Round to the nearest ten-thousandth.
P(t)=e^-(2/3)t
(a) P(-3) =

(b) P(7) =

(c) P(1/2) =

Question

Evaluate the following function at the indicated values. Round to the nearest ten-thousandth.
P(t)=e^-(2/3)t
(a)    P(-3) =

(b)    P(7) =

(c)    P(1/2) =

amistre64 · Answer

$$e^x=1+x+\frac{x^{2}}{2!}+\frac{x^{3}}{3!}+\frac{x^{4}}{4!}+\frac{x^{5}}{5!}+...$$
might be useful :)

anonymous · Answer

?

amistre64 · Answer

seeing how e^x is a rather hard thing to compute as is; we can turn it into a polynomial of approximate value.

amistre64 · Answer

but that is neither here nor there

amistre64 · Answer

-2/3 * -3 = 2

e^2 = 1+2+4/2+8/6+16/24 .... etc

anonymous · Answer

okay so step by step
e^-(2/3)-3
-2/3 * -3
2
e^2=7.389

amistre64 · Answer

yep

amistre64 · Answer

as long as the rounding is good ;)

anonymous · Answer

sweet thank you

amistre64 · Answer

and of course the others carry along the same concept ...

anonymous · Answer

yes thank you