Question

use quadratic formula 2x^2-3x=-10

Answer 1

2x^2 - 3x + 10 = 0

a = 2
b = -3
c = 10

Use the formula.

Answer 2

i have so far and i dont know if this is correct 8-27+10

Answer 3

This problem does not have real roots.

Answer 4

Determinant = 3^2 - 4*2*10 = 9-80 = -71.

Answer 5

i have to use a solution set . i dont have any complex numbers in terms of (i)?

Answer 6

no real roots, means that the roots are complex

Answer 7

since completing the square is proof of the quad formula:

2x^2 -3x = -10

x^2 -(3/2)x = -5

x^2 -(3/2)x+(3/4)^2 = -5+(3/4)^2

(x-(3/4))^2 = -5+(3/4)^2

x-(3/4) = +- sqrt(-5+(3/4)^2)

x = (3/4) +- sqrt(-5+(3/4)^2)

Answer 8

the wolf compacts that to:

\[\frac{3\pm i \sqrt(71)}{4}\]

Answer 9

is that the answer? ive use the (i) in answers but this one has totally lost me