use quadratic formula 2x^2-3x=-10

Question

anonymous · Answer

2x^2 - 3x + 10 = 0

a = 2
b = -3
c = 10

Use the formula.

anonymous · Answer

i have so far and i dont know if this is correct 8-27+10

anonymous · Answer

This problem does not have real roots.

anonymous · Answer

Determinant = 3^2 - 4*2*10 = 9-80 = -71.

anonymous · Answer

i have to use a solution set . i dont have any complex numbers in terms of (i)?

amistre64 · Answer

no real roots, means that the roots are complex

amistre64 · Answer

since completing the square is proof of the quad formula:

 2x^2 -3x = -10

 x^2 -(3/2)x = -5

 x^2 -(3/2)x+(3/4)^2 = -5+(3/4)^2

 (x-(3/4))^2 = -5+(3/4)^2

 x-(3/4) = +- sqrt(-5+(3/4)^2)

 x = (3/4) +- sqrt(-5+(3/4)^2)

amistre64 · Answer

the wolf compacts that to:

$$\frac{3\pm i \sqrt(71)}{4}$$

anonymous · Answer

is that the answer?  ive use the (i) in answers but this one has totally lost me