Help!
Find the center and the radius of the circle.
x2 + (y + 3)2 = 25
A) C(0, -3); r = 25
B) C(0, 3); r = 5
C) C(3, 0); r = 5
D) C(0, -3); r = 5
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OpenStudy (anonymous):
i know first you factor
OpenStudy (turingtest):
\[(x-h)^2+(y-k)^2=r^2\]is a circle radius r with center at (h,k) identify h and k and r, then you have your answer
OpenStudy (turingtest):
no factoring necessary ;)
OpenStudy (anonymous):
huh really because you have a 2(y+3) dont you need to distrubute that first
OpenStudy (lalaly):
\[x^2+(y+3)^2=25\]
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OpenStudy (turingtest):
lol, yes it would seem that way, but I know they mean
\[x^2 + (y + 3)^2 = 25\]
otherwise it would not be a circle.
people get lazy and just copy and paste questions, so it looks like a coefficient.
OpenStudy (fools101):
it B right?!
OpenStudy (anonymous):
oh its an exponent
OpenStudy (anonymous):
shoot
OpenStudy (lalaly):
its D
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OpenStudy (fools101):
why is it D -3? i thought it would be B isn't the 3 positive?
OpenStudy (turingtest):
careful about the minus sign!\[x^2+(y+3)^2=25=x^2+(y-(-3))^2=25\]so k=-3
OpenStudy (lalaly):
look at what turingtest wrote at the begining
25 = r^2
so r=5
and the general form of the circle is\[(x-h)^2+(y-k)^2=r^2\]
the center is (h,k)