Question

G(x)= 2x^2 + 1
x + 3
what is the vertical asymptote????? is it 2/3?

Answer 1

If there is nothing in denominator then vertical asymptote is 0 for this equation.

Answer 2

the bottom of the equation is x-3 correct? your vertical asymptote happens when the bottom part of the equation is 0. therefore since you need x+3 = 0, x has to be something that will cancel the 3 and therefore must be -3. so your vertical asymptote is at -3

Answer 3

OH! i've been doing it all wrong and not setting it equal to zero! thank you!