Question

Still having problems with this one. 8(z-3)=2(z+12) Is this the right answer? So do I add the 8z and 2z together?

Answer 1

What was the original question?

Answer 2

8(z-3)=2(z+12)

Answer 3

z = 8

Answer 4

Need to know once I *8z and 2z do I do I add the 8 and 2?

Answer 5

8(z-3)=2(z+12)
8Z-24=2Z+24
8Z-2Z =24+24
6Z=48
Z=8

Answer 6

8*5=2*20

Answer 7

If you're trying to solve for z you have to distribute the 8 and the 2.
8(z-3)=2(z+12)
=> 8z-24=2z+24
Then solve for z: subtract 2z from each side and add 24 to each side
6z=48
Divide each side by 6:
z=8

Answer 8

Thanks I get it now

Answer 9

\[8(z-3)=2(z+12) \]distributive property
\[8z-24=2z+24\] subtract 2z from both sides
\[8z-2z-24=2z-2z+24\]
\[6z-24=24\] add 24 to both sides
\[6z-24+24=24+24\]
\[6z=48\] divide both sides by 6
\[\frac{6z}{6}=\frac{48}{6}\]
\[z=8\]

Answer 10

\[8(z-3)=2(z+12)\]
I would divide 2 on both sides first
\[4(z-3)=z+12\]
Now I would distribute 4(z-3)=4z-12
\[4z-12=z+12\]
Subtract z on both sides
\[3z-12=12\]
Add 12 on both sides
\[3z=24\]
Divide 3 on both sides
\[z=8\]