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3x+2+x<1+2x-7
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How far were you able to go with this problem before getting stuck?
2x<-9
3x+2+x<1+2x-7 4x+1<2x+-6 4x+1-1<2x-6-1 4x<2x-7 4x<-7-2x 4x-2x<-7 2x<-7
so x = -7/2right ?
3x+2+x<1+2x-7 4x+1<2x+-6 ERROR :( should be ... 4x +2 < 2x -6
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oh sorry
it would be 2x<-8 -8/2
x < -4
Visually you can see this by going to http://www.wolframalpha.com and typing plot 3x+2+x, 1+2x-7 Note that at x = -4 the functions cross and it is precisely after x = -4 where y = 3x+2+x is less than y= 1+2x-7.
okay . so as a interval notation I would put (4,infinity]
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negative four. And the infinity would have a ")" instead of a "]" because you can't include infinity in an interval.
so, (4,infinity) ?
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