Question

Five candidates - A, B, C, D and E were in an election. Candidate A was elected with 30 votes, B placed second and E was in last with 3 votes. if 59 votes were cast, and no two candidates had the same number of votes, what is the smallest number of votes that B could have received ? Please show full work

Answer 1

59-3-30=26
26 votes are left

for B C and D

(a) +(a-1)+(a-2)=26

B C D
10+9+7=27

10+9+7

Answer 2

so 10

Answer 3

what are you subbing for a ?

Answer 4

A=30
B=10
C=
D=
E=3

Answer 5

ok hold on im sorry i don't understand this part (a) +(a-1)+(a-2)=26 what exactly are you doing there ?

Answer 6

26 is remaing votes after candidate a , b and e

Answer 7

ohh ok thank you ! :D

Answer 8

but wouldnt B be 7 in that case ? since it's the least amount of votes b could have received ?

Answer 9

but B is highest

Answer 10

** higher than C D E

Answer 11

ohh true okay then thanks :D can u do me a favor and answer some of the questions i posted up http://openstudy.com/#/updates/4edec488e4b05ed8401abf67