I need help with a 6th grade probability question. If three fair coins are tossed at the same time, what is the probability that 1 will show heads and two will show tails?
Can anyone help with this?
yes we can do this
there are 8 possibilities when three coins are tossed, and since that is a fairly small number we can actually list them h, h, h h, h, t h, t , h t, h, h h, t, t t, h, t t, t, h t, t, t of these, 3 have one have one head and two tails, so your probability is \[\frac{3}{8}\]
there is a snappier way to do this, but for 6th grade this should make the most sense
I see that there are 4 possible outcomes if you are tossing them at the same time. That would eliminate the doubles of h,t,h and t,h,h and t,h,h and h,t,h. Right?
"outcomes" in this case means all the possibilities for the heads or tails on the three coins. there are 2 for each coin (heads or tails) so by the "counting principle' there are \[2\times 2\times 2=8\] possibilities total. they are the ones i listed. hope that helps
Thank you for the help. 3/8 is one of the answers.
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