Question

solve and show steps 5(1.06^2x+1)=11

Answer 1

is this
\[5\times 1.06^{x+1}=11\]?

Answer 2

close its 5 X 1.06^2x+1=11

Answer 3

the +1 is out at the end?

Answer 4

its 1.06 raised 2x+1

Answer 5

\[5\times (1.06)^x+1=11\]
\[5\times (1.06)^x=10\]
\[(1.06)^x=2\]
\[x=\frac{\ln(2)}{\ln(1.06)}\]

Answer 6

thats incorrect

Answer 7

\[5\times 1.06^{x+1}=11\]
\[1.06^{x+1}=\frac{11}{5}=2.2\]
\[x+1=\frac{\ln(2.2)}{\ln(1.06)}\]
\[x=\frac{\ln(2.2)}{\ln(1.06)}-1\]

Answer 8

you are forgetting the 2

Answer 9

5(1.06^2x+1)=11

Answer 10

the answers should be 6.2657 but i dont know how to get it

Answer 11

5(1.06^2x+1)=11
=5*1.06^2x+5=11
=5*1.06^2x=11-5=6
=1.06^2x=6/5
Take log of both sides
2xlog(1.06)=log(6/5)
2x=log(6/5)/log(1.06)=3.129
x=1.5645

Answer 12

i'll ask my teacher in class today

Answer 13

http://openstudy.com/?F1235834802255UAVKIJ=_#/updates/4ee2419be4b0a50f5c5624fa here i asked and this girl answered it right. i had to do this problem in class.

Answer 14

so it's right. :)