yes final project =sembreak ^^ obtain the positive solution less than 360 degree 1. sec^2 x-4=0 2. cot^2x=3 3. 2cos^2x=cosx 4. cot^2x=cotx 5. 4sin^2x-3=0
congratz sembreak ^^ hope many will answer ^^ god bless ^^
\[sec^2x - 4=0\]\[\Leftrightarrow\frac{1}{cos^2x}=4\]\[\Leftrightarrow \frac{1}{4}=cos^2x\]
<> <<<<is this equivalent? yehey 4 more to go
The \(\Leftrightarrow\) sign means that the two lines 'mutually imply' each other, which is a fancy way of saying that they effectively mean the same thing.
Incidentally, what did you get for x when you solved that?
from my project 1-40 this 5 question is 36-40.. so meaning i dont have an idea sory this is the hardest part
Well if you have \[\frac{1}{4}=cos^2x\], then you can take the square root of both sides:\[\Leftrightarrow \pm\frac{1}{2}=cosx\]|dw:1323259692157:dw| Which gives you 4 different solutions for x, each of which is equally valid. What are those 4 solutions?
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