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Mathematics 9 Online
OpenStudy (ksaimouli):

sinx/cscx+cosx/secx=sinxcscx

OpenStudy (ksaimouli):

prove lhs=rhs

OpenStudy (anonymous):

is that (sinx/cscx)+(cosx/secx) = sinxcscx? if so that is the Pythagorean identity. hope that helps

OpenStudy (ksaimouli):

but identites should use when it is squares

OpenStudy (anonymous):

cscx = 1/sinx so sinx/csx = sin^2x

OpenStudy (ksaimouli):

how did u get

OpenStudy (anonymous):

its easier if you start with rhs =sinxcscx =sinx(1/sinx) =1 =sin^2x + cos^2x =sinx/(1/sinx)+cosx/(1/cosx) =sinx/cscx + cosx/secx

OpenStudy (anonymous):

easier for me i should say..

OpenStudy (ksaimouli):

why didu =sinx/(1/sinx)+cosx/(1/cosx)

OpenStudy (anonymous):

oh.. |dw:1323301898209:dw|

OpenStudy (anonymous):

sorry for the crappy drawing

OpenStudy (anonymous):

you can skip that line if you see it.. i just wrote it out just incase

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