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sinx/cscx+cosx/secx=sinxcscx
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prove lhs=rhs
is that (sinx/cscx)+(cosx/secx) = sinxcscx? if so that is the Pythagorean identity. hope that helps
but identites should use when it is squares
cscx = 1/sinx so sinx/csx = sin^2x
how did u get
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its easier if you start with rhs =sinxcscx =sinx(1/sinx) =1 =sin^2x + cos^2x =sinx/(1/sinx)+cosx/(1/cosx) =sinx/cscx + cosx/secx
easier for me i should say..
why didu =sinx/(1/sinx)+cosx/(1/cosx)
oh.. |dw:1323301898209:dw|
sorry for the crappy drawing
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you can skip that line if you see it.. i just wrote it out just incase
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