I need a step by step guide on solving: 3=x+sqrt of 2x-3

What I have done:
3=x+sqrt of 2x-3
3-x=sqrt of 2x-3
(3-x)^2 = (sqrt of 2x-3)^2
9-x^2 = 2x-3
12-x^2-2x = 0
x^2+2x-12 = 0
x(x+2) = 12
x = 12, x+2 = 14 T

he correct answer is x = 2, but I don't know what I did wrong. I only have ten minutes to figure this out.

Question

I need a step by step guide on solving: 3=x+sqrt of 2x-3

What I have done: 
3=x+sqrt of 2x-3 
3-x=sqrt of 2x-3 
(3-x)^2 = (sqrt of 2x-3)^2 
9-x^2 = 2x-3 
12-x^2-2x = 0 
x^2+2x-12 = 0 
x(x+2) = 12 
x = 12, x+2 = 14 T

he correct answer is x = 2, but I don't know what I did wrong. I only have ten minutes to figure this out.

anonymous · Answer

line 4 is where your mistake is