Question

my last question attached

Answer 1

well, this is a correct answer , but not in the form you need
\[\int _{-\frac{\pi }{2}}^{\frac{\pi }{2}}\int _0^4rdrd\theta -\int _{-\frac{\pi }{2}}^{\frac{\pi }{2}}\int _0^2rdrd\theta\]

Answer 2

this may just do the trick
\[\int _{-\frac{\pi }{2}}^{\frac{\pi }{2}}\int _2^4rdrd\theta\]

Answer 3

i'll try and see

Answer 4

yup...all was correct

Answer 5

so burn the textbook now?

Answer 6

i've had it for over a year....i'm so glad to be getting rid of it

Answer 7

we use same book for calc 1 2 and 3

Answer 8

i'm gonna take calc 4...but at least there's a different book involved

Answer 9

calc 4 ?

Answer 10

yea our school has a calc 4.....it's mainly just proofs though and calc 3 again

Answer 11

yea...just got my final left in that...i actually enjoyed diff eq a lot

Answer 12

I got diff eq and physics final tomorrow

Answer 13

yea...i got my physics final saturday.....not really lookin forward to that

Answer 14

ur in physics 1?

Answer 15

no, physics 2

Answer 16

oh god even worse

Answer 17

i got that in the spring

Answer 18

ready to suffer

Answer 19

i've hard

Answer 20

i've also heard physics 1 is useless in physics 2

Answer 21

yeah, they are different

Answer 22

but i apparently get to electrify stuff

Answer 23

calc 3 is useful in physics 2

Answer 24

things like vector integral, surface integral, ....

Answer 25

sigh...

Answer 26

alright...well thanks for your help with those...i'm gonna enjoy my tv for a little while

Answer 27

yep, good luck on your tests

Answer 28

u too :)